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z^2-0.18z-0.18=0
a = 1; b = -0.18; c = -0.18;
Δ = b2-4ac
Δ = -0.182-4·1·(-0.18)
Δ = 0.7524
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.18)-\sqrt{0.7524}}{2*1}=\frac{0.18-\sqrt{0.7524}}{2} $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.18)+\sqrt{0.7524}}{2*1}=\frac{0.18+\sqrt{0.7524}}{2} $
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